#### Yes, 25 cmA systems administrator needs to allocate storage across three servers. Server A can store 1.2 terabytes (TB), Server B can store 2.8 TB, and Server C can store 3.5 TB. If 40% of Server A, 65% of Server B, and 55% of Server C are already used, how much free space remains across all servers combined?

Sun, 19 Apr 2026 14:28:42 +0000

**#### Yes, 25 cmA systems administrator needs to allocate storage across three servers. Server A can store 1.2 terabytes (TB), Server B can store 2.8 TB, and Server C can store 3.5 TB. If 40% of Server A, 65% of Server B, and 55% of Server C are already used, how much free space remains across all servers combined?**
Gaining attention in U.S. data infrastructure circles, this question reflects a common challenge among systems admins managing distributed storage environments. With organizations increasingly relying on modular server setups for scalability and redundancy, understanding efficient space allocation is no longer optional—it’s strategic. Properly calculating free space ensures optimal performance, avoids costly overprovisioning, and supports smooth operations across critical systems. **Why This Question Matters in U.S. IT Infrastructure**
Storage optimization remains a top priority for IT teams across industries, especially as hybrid cloud models and edge computing drive data demands upward. When server utilization hits thresholds—like 40%, 65%, or 55%—admins must assess how much unused capacity is truly available. Knowing this allows proactive planning, reduces risk of bottlenecks, and supports data lifecycle management. In a mobile-first, always-connected environment, efficient storage directly impacts system responsiveness and reliability. **Understanding Current Usage and Free Space**
- Server A: Stores 1.2 TB with 40% used → Free space: 60% of 1.2 TB = 0.72 TB
- Server B: Stores 2.8 TB with 65% used → Free space: 35% of 2.8 TB = 0.98 TB
- Server C: Stores 3.5 TB with 55% used → Free space: 45% of 3.5 TB = 1.575 TB Combined free space: 0.72 + 0.98 + 1.575 = **3.275 TB**