f\left(-\frac32\right) = 4\left(-\frac32 + \frac32\right)^2 = 4 \cdot 0 = 0 - Treasure Valley Movers
Understanding the Mathematical Expression: f(–3/2) = 4(–3/2 + 3/2)² = 0
Understanding the Mathematical Expression: f(–3/2) = 4(–3/2 + 3/2)² = 0
Mathematics often reveals elegant simplicity beneath seemingly complex expressions. One such example is the function evaluation:
f(–3/2) = 4(–3/2 + 3/2)² = 0
At first glance, this equation may appear puzzling, but careful analysis uncovers its underlying logic. This article explains step-by-step how and why this expression simplifies to 0, showing the power of basic algebraic operations.
Understanding the Context
The Function: Step-by-Step Breakdown
The function f(x) at x = –3/2 is defined by the formula:
f(–3/2) = 4(–3/2 + 3/2)²
Key Insights
Let’s simplify the expression inside the parentheses:
–3/2 + 3/2 = 0
This is simply the sum of a number and its inverse on the number line—thingally zero.
Evaluating the Square
🔗 Related Articles You Might Like:
📰 You’re Not Ready for This territoires of Fury Angry Meme! 📰 5) The Most Infuriating Angry Meme Ever – It’ll Make You Rant Nonstop! 📰 Angry Birds Just Went OFF THE RAD—Here’s Why You’re Angry Too! 📰 Verizon Prepaid Refill 📰 Palia Tips And Tricks 📰 My Fidelity Benefits 📰 Feudalism 2 Download 📰 Can You Deposit A Check In An Atm 📰 Wellsfargo Com Cardholders Payment 📰 Big Bigfoot Games 📰 From Sweet Heroes To Hot Forces The Untold Secrets Of Powerpuff Girls Characters 2685551 📰 Unreal Tournament Iii 📰 Usd To Riyal 📰 The Great Gilly Hopkins Cast 📰 Big Data Big 📰 Wells Fargo Plainview Tx 📰 Pdga Live Scoring 📰 Bank Of AmericdaFinal Thoughts
Next, we square the result:
(–3/2 + 3/2)² = 0² = 0
Since any number squared equal to zero remains zero, this directly yields:
f(–3/2) = 4 × 0 = 0
Why This Matters
This example demonstrates a foundational principle in algebra: when an expression inside parentheses evaluates to zero, squaring it results in zero—then scaling by any real number (in this case, 4) preserves this property.
In broader terms, such evaluations help identify roots of functions, test symmetry, or simplify complex expressions in calculus and engineering.