**Alternative interpretation: threshold is 25 out of 100, but formula
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📰 Solution: Start by solving $ 2\cos(2\theta) + 1 = 0 \Rightarrow \cos(2\theta) = -\frac{1}{2} $. The general solutions for $ 2\theta $ are $ 2\theta = 120^\circ + 360^\circ k $ or $ 2\theta = 240^\circ + 360^\circ k $, where $ k \in \mathbb{Z} $. Dividing by 2, $ \theta = 60^\circ + 180^\circ k $ or $ \theta = 120^\circ + 180^\circ k $. For $ \theta \in [0^\circ, 360^\circ] $, the solutions are $ 60^\circ, 120^\circ, 240^\circ, 300^\circ $.
📰 \boxed{60^\circ, 120^\circ, 240^\circ, 300^\circ}
📰 Question: Let $ z^4 + z^2 + 1 = 0 $. Express the maximum imaginary part of a root as $ \sin \theta $, where $ \theta \in [0^\circ, 360^\circ] $, reflecting harmonic analysis in linguistic frequency models.
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