The area \( A \) of an equilateral triangle with side length \( s \) is given by \( A = \frac{\sqrt{3}}{4} s^2 \). The radius \( r \) of the inscribed circle in an equilateral triangle is \( r = \frac{s\sqrt{3}}{6} \). The area of the circle is \( \pi r^2 = \pi \left(\frac{s\sqrt{3}}{6}\right)^2 = \frac{\pi s^2 \cdot 3}{36} = \frac{\pi s^2}{12} \). The ratio of the area of the triangle to the area of the inscribed circle is:

Fri, 17 Apr 2026 23:36:31 +0000

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