Let $ M $ be the midpoint of the chord $ AB $. Then triangle $ OMA $ is a right triangle, with hypotenuse $ OA = 5 $ meters and leg $ AM = \frac{6}{2} = 3 $ meters. Let $ d $ be the distance from the center to the chord, which is $ OM $.

Fri, 17 Apr 2026 17:52:56 +0000

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