But we must check if all such \( y \) are attainable. From \( x^2 = \frac{y+1}{y-1} \), for any \( y \ne 1 \), there's a real \( x \) if the right-hand side is non-negative — which holds when \( y > 1 \) or \( y \leq -1 \).

Mon, 20 Apr 2026 05:14:12 +0000

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