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2048 → 1024 - Treasure Valley Movers

📅 April 16, 2026 👤 scraface

Apr 16, 2026

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📌 We want the probability that **at least two** channels allow sufficient flow, i.e.,

📌 P(\text{at least 2 flows}) = P(A \cap B \cap \overline{C}) + P(A \cap \overline{B} \cap C) + P(\overline{A} \cap B \cap C) + P(A \cap B \cap C)

📌 $ P(A \cap B \cap \overline{C}) = 0.4 \cdot 0.5 \cdot (1 - 0.6) = 0.4 \cdot 0.5 \cdot 0.4 = 0.08 $

📌 $ P(A \cap \overline{B} \cap C) = 0.4 \cdot (1 - 0.5) \cdot 0.6 = 0.4 \cdot 0.5 \cdot 0.6 = 0.12 $

📌 $ P(\overline{A} \cap B \cap C) = (1 - 0.4) \cdot 0.5 \cdot 0.6 = 0.6 \cdot 0.5 \cdot 0.6 = 0.18 $

📌 $ P(A \cap B \cap C) = 0.4 \cdot 0.5 \cdot 0.6 = 0.12 $

📌 Now summing these:

📌 P(\text{at least 2 flows}) = 0.08 + 0.12 + 0.18 + 0.12 = 0.5

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