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Home » \( P = 10,000 \) (principal) - Treasure Valley Movers

\( P = 10,000 \) (principal) - Treasure Valley Movers

📅 April 15, 2026 👤 scraface

Apr 15, 2026

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But 564 = 4×141 → no perfect square.
Wait — maybe the sum is 365? Then 3x²+2=365 → 3x²=363 → x²=121 → x=11...
But problem says 425.
Alternatively, 3x² + 2 = 425 → x²=141 → smallest is √141 − 1 ≈ 10.87 →...
But the only way is to accept the algebraic solution.
The smallest integer is \( \sqrt{141} - 1 \), but must be integer — co...
Wait — perhaps three consecutive odd integers? But not specified.
Alternatively, maybe the problem meant sum of cubes? Unlikely.
Wait — let's try x = 11: sum = 365
x = 12: 144+169+196=509

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